convert the above expression into this graph

I want to convert the above expression into this graph.
Can you help me? TT

Answer 1

[Torsten]

I'll show you how to solve for theta2 given theta from the equation

sin(theta2-theta)+exp(-theta2/(omega*tau))*sin(theta)=0

From the graph I guess this is not exactly what is meant. So you have to explain yourself in more detail.

omega = 1;
tau = 100;
theta = linspace(0,pi/2);
fun = @(theta2,theta)sin(theta2-theta)+exp(-theta2/(omega*tau))*sin(theta);
theta20 = pi;
for i = 1:numel(theta)
    theta2(i) = fzero(@(theta2)fun(theta2,theta(i)),theta20);
    theta20 = theta2(i);
end
plot(theta*180/pi,theta2*180/pi)
xlim([0 90])

[서연]

You are my GOD.

Very very thank you.

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