How to extract date time from format unique to InputFormat?
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Muha
on 12 Nov 2024 at 14:26
Commented: Cris LaPierre
on 21 Nov 2024 at 21:46
I have data set extracted in the form ´05/17/24 04p:48:15.8148625´. These data sets are not fond in the InputFormat list, contains a 'p' for postmeridian, and has seconds up to 7 decimal places. I am ok if it is inevitable to round-off the seconds, however, I will be working with several formats and the manual way of extracting parts of strings, joining them together in InputFormat list is quite hectic and it slows down my code. Is there a way we can simply use datetime command to convert the text into datetime? I will appreciate your help. Thanks.
load('data_imp.mat');
dttime = datetime(data_imp,"InputFormat","MM/dd/uu 'T'HH:mm:ss.SSSSSSS");
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Accepted Answer
Shashi Kiran
on 12 Nov 2024 at 15:39
To convert your data into "datetime" format in MATLAB, you can use "regexprep" to handle the PM adjustment. Here’s how:
load('data_imp.mat')
% Adjust PM hours
data_adj = regexprep(string(data_imp), '(\d{2})p:', '${num2str(str2double($1) + 12, ''%02d'')}:');
% Convert to datetime
dttime = datetime(data_adj, 'InputFormat', 'MM/dd/yy HH:mm:ss.SSSSSSS')
For more details on "regexprep", refer to the documentation here: https://www.mathworks.com/help/matlab/ref/regexprep.html
Hope this helps!
More Answers (2)
Cris LaPierre
on 12 Nov 2024 at 15:26
The format used to represent am/pm (04p:48:15.8148625) is not one recognized by MATLAB. You therefore need to manipulate your data into a format that MATLAB can recognize.
My approach would be
- capture which rows contain pm times
- remove the am/pm designation
- convert times to datetimes
- add 12 hours to rows containing pm times
load('data_imp.mat')
data_imp
% capture pm times
pmTms = cellfun(@(x) contains(x,'p:'),data_imp);
% remove am/pm designation
data_imp = replace(data_imp,lettersPattern + ':',':')
% convert to datetime
dttime = datetime(data_imp,"InputFormat","MM/dd/yy hh:mm:ss.SSSSSSS");
% add 12 hours to pm times
dttime(pmTms) = dttime + hours(12)
Peter Perkins
on 21 Nov 2024 at 21:44
Another possibility:
str = "05/17/24 04p:48:15.8148625"
str = replace(str,"p","pm")
datetime(str,InputFormat="MM/dd/yy hha:mm:ss.SSSSSSS")
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