# solving a matrix exponential equation

6 views (last 30 days)
Alfonso Nieto-Castanon on 17 Jun 2015
Commented: Star Strider on 17 Jun 2015
I know this is perhaps a "methods" question rather than a purely "Matlab" question, but does anybody know or could point me towards a way to estimate/fit the parameters of a matrix exponential equation?
In particular, if x is a NxM matrix representing a vector timeseries (each column x(:,n) is an observed N-dimensional vector) I would like to fit this data to a model of the form:
x(:,n) = expm(A*n)*b;
(note that this is matrix exponentiation, not element-wise exponentiation) where the matrix A (NxN matrix) and the vector b (Nx1 vector) are parameters to be estimated from the data in a way that minimizes the mse of the fit:
x_fit = cell2mat(arrayfun(@(n)expm(A*n)*b, 1:size(x,2),'uni',0));
err = mean(sum(abs(x_fit-x).^2,1),2);
Thank you for any pointers/thoughts/comments!

Star Strider on 17 Jun 2015
Very interesting problem! The solution parallels the technique used to fit differential equations using curve fitting functions. It is necessary to use lsqcurvefit for your function, because it supports matrix dependent variables. The code is straightforward.
It runs, but you will have to experiment with it to get it to work with your parameter set and data:
function y = matexp(b,t)
f = @(b,t) expm([b(1) b(2); b(3) b(4)]*t)*[b(5); b(6)];
for k1 = 1:N
y(:,k1) = f(b, t(k1));
end
end
B0 = rand(6,1);
N = 20;
t = linspace(0, 2*pi, N);
x = [cos(t); sin(t)];
B = lsqcurvefit(@matexp, B0, t, x)
for k1 = 1:N
x2(:,k1) = f(B, t(k1));
end
figure(1)
plot(t, x)
hold on
plot(t, x2)
hold off
grid
I ran these in a nested function file, but you will probably find it easier to save ‘matexp’ as a separate function file.
##### 2 CommentsShowHide 1 older comment
Star Strider on 17 Jun 2015
As always, my pleasure!