check without using for loop

hi, I want to check if an element =0 or not, then convert it into binary without use for loop, because I have large size of data can do that? data is array with size m*n

for i=1:m
   k2=1;
   for j=1:n
     if data(i,j)~=0
       x     = dec2bin(~0,data(i,j), 16);
       y     = transpose(reshape(x, 4, 4)); 
       y1    = bin2dec(y);
       aa(1) = int2aa(y1(1));
       aa(2) = int2aa(y1(2));
       aa(3) = int2aa(y1(3));
       aa(4) = int2aa(y1(4));
       aa1=[aa(1) aa(2) aa(3) aa(4)];
       aaseq1(i,k2)={aa1};
       k2=k2+1;
     end
   end
 end

thanks in advance

[Jan]

This code is not valid: DEC2BIN accepts 2 inputs only.

You can create a small and fast lookup-table locally instead of calling INT2AA 4 times. Pre-allocation is also a very good idea. "aaseq1[i,k2}=aa1"; is faster than "aaseq1(i,k2)={aa1};".

[huda nawaf]

thanks,

but when I used

aaseq1{i,k2}=aa1

and use

dlmwrite('codweb.txt',aaseq1);

I got this error

??? Error using ==> dlmwrite at 112

The input cell array cannot be converted to a matrix.

Error in ==> webproc1 at 24

dlmwrite('codweb.txt',aaseq);

Answer 1

[Andrei Bobrov]

[m,n]=size(data);
aaseq1 = cell(m,n);
[d,ix] = sort(data,2,'descend');
ix(d==0)=inf;
[i2,i2]=sort(ix,2);
d1 = d(bsxfun(@plus,(i2-1)*m,(1:m)'));
t = d1~=0;
d2 = rem(floor(d1(t)*pow2(-15:0)),2);
d3 = blockproc(d2,[1 4],@(block_struct)block_struct.data*pow2((3:-1:0)'));
aaseq1(t) = cellstr(int2aa(d3));