How can I get values outside of -90,90 degrees range when using asin?

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Ophion Dragon on 15 Sep 2015

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Answered: Walter Roberson on 15 Sep 2015

Trying to get an answer of 147 degrees but the program always returns 33 degrees (within the range).

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Walter Roberson on 15 Sep 2015

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If you know you are in that quadrant then use (180 - asind(x))

If you do not know which quadrant then you need to know the sign() of the opposite and the radius in order to calculate the quadrant.

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