reading dates and time
64 views (last 30 days)
Show older comments
Hi Struggling with this. Got a clean financial time series csv, reads like this:
03/01/2006,08:00,40.10,40.42
etc. in one minute intervals, with some minutes missing
How do I import this properly so I can plot prices on a simple line graph with dates and times. Tried all the importfunctions and textscan to no avail. Thanks for any help in advance
Al
1 Comment
reddy
on 2 Jun 2015
hi everyone,
I am also having similar problem but my problem is I am having data every two minutes time interval with the format
9/10/2013 4:00 721.19141 4.999999523 0 35.29541 -300 -0.011333227
9/10/2013 4:02 721.67969 4.999999523 0 35.43457 -300 0.561000109 ....
Now i would like to average the data to each hour and save.
Now the problem is there are some data missing. how to overcome this problem??
Answers (6)
Walter Roberson
on 21 Dec 2011
thecells = textscan(fid, '%f/%f/%f,%f:%f,%f,%f', 'CollectOutput', 1);
thecells = thecells{1};
times = datenum([thecells(:,3), thecells(:,2), thecells(:,1), thecells(:,4), thecells(:,5), zeros(size(thecells,1),1)]);
price1 = thecells(:,6);
price2 = thecells(:,7);
The times that you would get out would be in serial date number, which is the format most suitable for date plots.
The zeros(size(thecells,1),1) part of the datenum call is to insert 0 as the second for each line, as it happens that the conversion from datevec format (that I am constructing) to datenum needs the seconds fields.
I have guessed in the above that the order is Day Month Year; if it is Month Day Year then exchange the 2 and the 3 in the times calculation.
0 Comments
alex
on 22 Dec 2011
3 Comments
Matt Tearle
on 22 Dec 2011
That drives me nuts -- seems to defeat the purpose of 'CollectOutput' (IMNSHO).
Dr. Seis
on 22 Dec 2011
Also a neat trick with reading date/time info:
date_str = '03/01/2006,08:00:00,40.10,40.42';
date_serial = datenum(date_str,'mm/dd/yyyy,HH:MM:SS');
See "doc datenum" for more examples!
0 Comments
alex
on 23 Dec 2011
2 Comments
Dr. Seis
on 28 Dec 2011
I was just pointing out another way to read date/time information from a string... if you know the ordering of the month,day,year,hour,minute,second and what sort of separator you have between them (i.e., "/" or ":" or "," or etc.) then "datenum" can read that string information without having to pull information out using "textscan". However, you also need other information from your string (the price info) so you would still need to use "textscan" to pull that info out. It was just a helpful hint to figure out the serial date/time with the fewest amount of keystrokes.
Just in case that wasn't what you were asking... typing "doc datenum" (without the quotes) at the command line will bring up the help page for "datenum".
Thanh Cao
on 5 Apr 2018
Edited: Walter Roberson
on 7 Apr 2018
I have a text file contain the date and time like this
20180405125901 (2018-April-05 12:59:01)
can matlab load the file and convert it to datetime like this 05-Apr-2018 12:59:01
1 Comment
Walter Roberson
on 7 Apr 2018
I am not completely clear as to whether the '(2018-April-05 12:59:01)' is part of the original file, or if only the 20180405125901 is ?
To convert t = 20180405125901 you can just do arithmetic:
rest = t;
t_sec = mod(rest, 100);
rest = (rest-t_sec)/100;
t_min = mod(rest, 100);
rest = (rest-t_min)/100;
t_hour = mod( rest, 100 );
rest = (rest - t_hour)/100;
t_day = mod(rest, 100);
rest = (rest - t_day)/100;
t_mon = mod(rest, 100);
rest = (rest - t_mon)/100;
t_year = rest;
after which you can use the components to format strings using datestr() or datetime()
Alternately, you can
datetime(sprintfc('%lu', t), 'InputFormat', 'yyyyMMddHHmmss', 'Format', 'dd-MMM-yyyy HH:mm:ss')
See Also
Categories
Find more on Timetables in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!