How can I search a binary array inside other bigger binary array?

For example I have the A array

A = [1 0 0 1 0,0 0 0 0 0,0 1 0 1 0,0 0 0 0 0]

I need to seach how many times is the B array in A.

B = [1 0,0 0]

[Jan]

Are you sure that both arrays are vectors? The commas might indicate, that you want matrices.

Would "4 times" be a satisfying answer?

[AMANECH77]

No, you´re right, they are matrices. And yes, 4 times would be a satisfying answer.

Answer 1

[Thorsten]

 A = [1 0 0 1 0;0 0 0 0 0;0 1 0 1 0;0 0 0 0 0]
 B = [1 0;0 0]

Embed A into a larger matrix of nans because nlfilter sets boundary values to 0; the following code is just valid for 2x2 matrices B

 A2 = nan(size(A)+2))
 A2(2:end-1, 2:end-1) = A;

 nnz(nlfilter(A2, [2 2], @(x) (isequal(x,B))))

[AMANECH77]

Thanks. That works perfect for my needs.

[AMANECH77]

I have a problem with the code. If a change matrix B, for example:

B = [0 0;0 0]

I don´t get the right number of times this pattern is in matrix A (in this case it must be find "1". Could you help me?

Thanks

[AMANECH77]

Thanks Thorsten.