Multi Struct to Matrix

From Structs of Arrays:
s(1).x = [1 2 3; 4 5 6; 7 8 9];
s(2).x = [11 12 13; 14 15 16; 17 18 19];
I would like to get a matrix made up of, say, the second rows only - without using a loop
ans = [4 5 6; 14 15 16]
But typing
s.x(2,:) or [s.x(2,:)] or {s.x(2,:)}
gives the error
"Expected one output from a curly brace or dot indexing expression, but there were 2 results."
Any help appreciated. Jack

2 Comments

Stephen23
Stephen23 on 18 Feb 2016
Edited: Stephen23 on 18 Feb 2016
I am not sure that those attempted syntaxes would make much sense anyway...
s.x
actually creates a comma separated list, like this:
s(1).x, s(2).x, ... s(end).x
It makes no sense to apply indexing to the last variable in a comma separated list:
A,B,C,D(:,2)
and then expect that the indexing is applied to all variables within the comma separated list. This would be counter-intuitive. The only logical place would be after the square brackets/curly braces, in which case this becomes a standard application of indexing into a single temporary variable, like this:
[s.x](:,2)
This is an enhancement that many people would like, but so far has not yet been implemented.
Jack
Jack on 18 Feb 2016
Makes sense. I voted up Walter's proposal.

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Answers (2)

cell2mat( arrayfun(@(c) c.x(2,:), (1:length(s)).', 'Uniform', 0) )

8 Comments

Jack
Jack on 18 Feb 2016
Thank you, I was hoping I had the wrong syntax but I see that Matlab simply can't do it.
Nice, just missing a reference to s. Should be
cell2mat( arrayfun(@(c) c.x(2,:), s(1:length(s)).', 'Uniform', 0) )
Could also be written more simply as
cell2mat( arrayfun(@(c) c.x(2,:), s.', 'Uniform', 0) )
I wonder why I didn't code
cell2mat( arrayfun(@(c) c.x(2,:), s(:), 'Uniform', 0) )
Ben Oeveren
Ben Oeveren on 31 Oct 2017
Edited: Guillaume on 31 Oct 2017
For everyone still interested. The following seems to do the job. But it is not specifically fast. It works even when you have a struct with multiple field layers. Just insert your desired string.
function m = struct2mat(s,fields)
% Convert a structure to a matrix.
% fields (string) - s(i).my1stfield.my2ndfield.my3thfield
% Ben van Oeveren,
m = [];
for i = 1:length(s)
mnew = eval(['s(i).' fields]);
m = [m;mnew];
end
end
Guillaume
Guillaume on 31 Oct 2017
Edited: Guillaume on 31 Oct 2017
@Ben,
Please format your code properly.
it's not specifically fast and worse it uses eval when it's not needed at all.
m = [];
fieldlist = strsplit(fields, '.');
for i = 1:numel(s)
m = [m; getfield(s(i), fieldlist{:}));
end
It would be better to get the list of field names as a cell array of individual fields rather than as a char array of field names joined by dots as this would avoid the need for the strsplit line.
Note that your code, and Walter's first answer, only work properly with vector structures, due to the problematic use of length.
Stephen23
Stephen23 on 31 Oct 2017
Edited: Stephen23 on 31 Oct 2017
Thank you good idea. Just tested the eval on timing. The difference in time is not really big.
For 106 fields, in total a double of 10883839x3 Elapsed time is 14.001423 seconds. eval Elapsed time is 13.644880 seconds. normal loop
Nevertheless, getfield and setfield seems like good alternative solution.
@Ben Oeveren: consider not just just the simple timing in a loop, but also that JIT does not work, debugging tools do not work, variable highlighting does not work, the security risk, etc.
And thinking that "my code does not need to be secure" is exactly why doing this is so easy:

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Jan
Jan on 18 Feb 2016
Edited: Jan on 18 Feb 2016
Walter's suggestion is compact and nice. Internally this contains loops also. So the actual problem I would solve is this:
... without using a loop
Create a loop, care for a proper pre-allocation, export this to a secific M-function if you want to keep you main program clean and lean.

1 Comment

Jack
Jack on 18 Feb 2016
I see. Braces would seem intuitive: would be nice to have such functionality in the future if possible...

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