How to use a loop for an array

My question is:
I have an array with values ranging from 0 to 200 something, and I need to find the average value for a set range of the data i.e. I need to find the average value for 0 to 1, the average value of the data for 1-2, and so on until it hits the end. I would like to save that information in a new matrix that I can look up later on.
Any help is appreciated.

2 Comments

What about the boundary points? E.g., if a value is exactly 1, do you want it to be part of the 0-1 average and also the 1-2 average? Or do you want these averages to be mutually exclusive?
I suppose the range should be greater than the lower bound, less than or equal to the upper bound. I'll have to try out your method.

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 Accepted Answer

If you have the Statistics and Machine Learning Toolbox, you can use grpstats(). It's a single line of code:
% Create sample data
r = 200 * rand(100000, 1);
% Now find means in every integer range.
means = grpstats(r, floor(r))

4 Comments

That may have worked like a charm, thank you very much. That was simple too!
Image Analyst
Image Analyst on 24 Mar 2016
Edited: Image Analyst on 26 Mar 2016
One point to note is that if there are absolutely no means in some range, then that element will be missing from means. So just be aware of that.
Is there a way to save the values used for each mean in an array so that I may apply further operations to that information?
In my code above, means is already an array. Do you mean like an array of those arrays? Like you want a 2D array or an array of structures?

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More Answers (1)

James Tursa
James Tursa on 23 Mar 2016
Edited: James Tursa on 23 Mar 2016
Does something like this do what you want?
n = ceil(max(values));
x = bsxfun(@ge,values(:),0:n-1) & bsxfun(@le,values(:),1:n);
averages = sum(bsxfun(@times,values(:),x)) ./ sum(x);
averages(isnan(averages)) = 0;

1 Comment

The ceil function is pretty cool. I like the idea of using the bsxfun, but how would I be able to calculate the average for the data with a value between 0 and 1, or 1 to 2 (and so on), using this function, for all the values in the array?

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Asked:

KK
on 23 Mar 2016

Commented:

on 26 Mar 2016

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