Why do i get an error in the Fixed Point Conversion Step?
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Pablo Medina
on 13 Jul 2016
Commented: Pablo Medina
on 14 Jul 2016
Error: The function 'HDLIFFT128' contains persistent variables 'ifft128' and has specialization 'HDLIFFT128_s1' associated with it. Function specializations containing persistent variables are not supported for fixed-point conversion. Consider rewriting your algorithm such that it does not use persistent variables within functions that require specialization.
I am trying to generate HDL Code from this main function.
function [out1,out2] = main(x,y,z)
%call subfunction 1
out1 = sub1(x);
%call subfunction 2
out2 = sub2(y,z);
end
Sub-function 2 code:
function [yOut,validOut] = HDLIFFT128(yIn,validIn)
%HDLIFFT128
% Processes one sample of data using the dsp.HDLIFFT System object(TM)
% yIn is a fixed-point scalar or column vector.
% validIn is a logical scalar.
% You can generate HDL code from this function.
persistent ifft128;
if isempty(ifft128)
ifft128 = dsp.HDLIFFT('FFTLength',128);
end
[yOut,validOut] = step(ifft128,yIn,validIn);
end
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Accepted Answer
Walter Roberson
on 13 Jul 2016
I would suggest breaking it up into two pieces, one of which constructs the ifft128 object, and the other of which expects that object to be always input.
3 Comments
Walter Roberson
on 13 Jul 2016
function ifft128 = init_HDLIFFT128
ifft128 = dsp.HDLIFFT('FFTLength',128);
function [yOut,validOut] = HDLIFFT128(yIn, validIn, ifft128)
[yOut,validOut] = step(ifft128,yIn,validIn);
The init function would be outside of any loop, and you would route its output to be an input of HDLIFFT128 that might be in a loop.
More Answers (1)
Bharath Venkataraman
on 13 Jul 2016
Pablo, splitting the function into a main function and calling the IFFT function from it resulted in HDL code generation. Here are the functions split up. Please replace the testbench and design files as needed.
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