Index exceeds matrix dimensions.

7 views (last 30 days)
f21=@(x)(exp(-x/3))/(4-cos(pi*x));
n=25; h=2.5/n; t=h*(0:n); f=f21(t).^2; T26=pi*h*(sum(f)-(f(1)+f(n+1))/2);
n=52; h=2.5/n; t=h*(0:n); f=f21(t).^2; T52=pi*h*(sum(f)-(f(1)+f(n+1))/2);
Can't figure why Index is exceeding the matrix dimensions. Since the graph goes up to 5.

Accepted Answer

Alexandra Harkai
Alexandra Harkai on 4 Nov 2016
Did you check what you get for f?
f21=@(x)(exp(-x/3))/(4-cos(pi*x));
This returns a scalar, so f will be of size 1*1. If you want element-wise division, then this will not fail:
f21=@(x)(exp(-x/3))./(4-cos(pi*x));

More Answers (0)

Categories

Find more on Fourier Analysis and Filtering in Help Center and File Exchange

Tags

No tags entered yet.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!