what will code line 2 and 3 will do in below code? fprintf('\​nInitializ​ing...\n')​; %1 strArray = java_array​('java.lan​g.String', numberOfIm​agesToProc​ess);%2 for k = 1 : numberOfIm​agesToProc​ess%3 File1 = [imagesFolder '\'];%4 File = [imageFiles

fprintf('\nInitializing...\n'); %1
strArray = java_array('java.lang.String', numberOfImagesToProcess);%2
for k = 1 : numberOfImagesToProcess%3
    File1 = [imagesFolder '\'];%4
    File = [imageFiles(k).name];%5
    strArray(k) = java.lang.String(File);%6
end

Answer 1

[Guillaume]

Why don't you ask the author or whoever gave you that code?

The code store the names of the files into a java array. Only the author can tell you why they decided to store them in a java array as opposed to matlab's built-in arrays (2d char array or cell array of 1d char arrays).

Only the author can also tell you why they waste time recalculating a constant in the loop.