Why does the code stop doing iterations?

When the car loan has been paid off, the student loan value goes to 0 as well.

clc; clear; % clear the command window and memory
x = 2000; % starting balance of the current account
r = 0.015/12; % the interest rate on the current account
sal = 28650; % graduate's salary
RPI = 0.017; % RPI value
liv = 1506; % monthly living expenses

stloan = 27000; % starting sum of the student loan
if sal<21000
    rep = 0; % monthly student loan repayment
    rs = RPI/12; % monthly student loan interest
elseif sal<41000
    rep = 0.09*(sal-21000)/12; % monthly student loan repayment
    rs = (RPI+0.03*(sal-21000)/20000)/12; % student loan interest
else
    rep = 0.09*(sal-21000)/12; % monthly student loan repayment
    rs = (RPI+0.03)/12; % monthly student loan interest
end

carloan = 15700; % starting sum of the car loan
carrep = 357; % monthly car loan repayments
carrs = 0.05/12; % monthly car loan interest

N = 120; % the number of months to consider
t = 1:N+1; % our timeline
xhist=zeros(1,N+1); % create a vector to hold the account history
xhist(1) = x;
sthist=zeros(1,N+1); % vector to hold the student loan history
sthist(1) = stloan;
carhist=zeros(1,N+1); % vector to hold the car loan history
carhist(1) = carloan;

for m=1:N % commands inside the loop are executed for each month
    x = (1+r)*x+sal/12; % apply the interest and pay in the salary
    stloan = (1+rs)*stloan; % apply the interest to the student loan
    carloan = (1+carrs)*carloan; % apply the interest to the car loan
    x = x-liv;
    if stloan-rep>0
        x = x-rep; % take money off the current account...
        stloan = stloan-rep; % ...and make student loan payment
    else
        x = x-stloan; % take the remainder off the current account...
        stloan = 0; % ...and close the student loan
    end
    if carloan-carrep>0
        x = x-carrep; % take money off the current account...
        carloan = carloan-carrep; % ...and make car loan payment
    else
        fprintf('Month of Final Car Loan Payment = %.2f\n',m); % print the month of final payment
        fprintf('Final Car Loan Payment = %.2f\n',carloan); % final loan payment
        x = x-carloan; % take the remainder off the current account...
        carloan = 0; % ...and close the car loan
        break
     end
    xhist(m+1) = x; % save the sum at the beginning of month m
    sthist(m+1) = stloan; % do the same for the student loan
    carhist(m+1) = carloan; % do the same for the car loan
end
fprintf('Balance = %.2f\n',x); % balance at the beginning of (N+1)th month
fprintf('Student Loan Balance = %.2f\n',stloan); % print the outstanding student loan balance
fprintf('Car Loan Balance = %.2f\n',carloan); % print the outstanding car loan balance

[the cyclist]

@Baja Laja, just want to let you know that deleting your questions after they have been answered (especially by two of the top contributors on the site) is an excellent way to ensure that your future questions will not be answered at all.

[Rena Berman]

(Answers Dev) Restored Question.

Answer 1

[the cyclist]

Because when m = 49, you hit the break command, and leave the for loop. See the documentation for break for details.

[Baja Laja]

When I remove the break in the code, it prints every car loan balance from m 49 to 120. How do I only terminate the car loan only once it been paid?

[Walter Roberson]

if carloan ~= 0

...

[Baja Laja]

Sorry I don't understand what you mean.

[Walter Roberson]

if carloan ~= 0
  if carloan-carrep>0
      x = x-carrep; % take money off the current account...
      carloan = carloan-carrep; % ...and make car loan payment
  else
      fprintf('Month of Final Car Loan Payment = %.2f\n',m); % print the month of final payment
      fprintf('Final Car Loan Payment = %.2f\n',carloan); % final loan payment
      x = x-carloan; % take the remainder off the current account...
      carloan = 0; % ...and close the car loan
      break
   end
 else
   %already finished paying off the car, do not do anything
 end