# matlab code

62 views (last 30 days)
noor on 10 Mar 2012
clear
clc
d1=120; d2=94;
J = imresize(I,[200 250]);
X = rgb2gray(I);
Y=X';
for k1=1:d1
for k2=1:d2
B(2*k1,k2)=X(k1, k2);
B(2*k1-1,k2)=floor((X(k1,k2)+X(2*k1-1,k2))/2);
end
end
imshow(B);
What's wrong with this code?? there is some wrong with the floor function what is it ???
Chandra Kurniawan on 10 Mar 2012
Please show me the error message!
noor on 10 Mar 2012
??? Attempted to access X(213,1); index out of bounds because size(X)=[212,320].
Error in ==> floor at 12
B(2*k1-1,k2)=floor((X(k1,k2)+X(2*k1-1,k2))/2);

Chandra Kurniawan on 10 Mar 2012
The error message sounds you accessed X(213,1) while the size of X is 212x320
X is a gray image generated from command : X = rgb2gray(I);
so, the original image I has 212x320 dimension.
noor on 10 Mar 2012
so what can i do ??
Chandra Kurniawan on 10 Mar 2012
You wrote the code d1=120 and also wrote B(2*k1,k2)
So, ideally the image must have minimum 2*120 x 94 dimension.
You can resize the image.
J = imresize(I,[240 94]);
Then followed with :
X = rgb2gray(J);

777 on 10 Mar 2012
your code has x(2*k1-1) ,so when the value of k1=120 you reach a value which is out of bounds for x.