Creating a hex array with 4 digit blocks from an array of integers
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I am using R2013 and need to convert a large decimal array into hex stings.
The decimal numbers can be any positive integer, and I need to convert each number, then display each as a minimum two byte string with preceding zeros (with more bytes shown as the number increases).
e.g. decimal "1" should show up as '0x0001',
decimal "69876" should show up as '0x0001 0x10F4'
I created a rather cumbersome loop that does this perfectly, but with large arrays it takes too long.
I can get part way to a non-loop implementation with this code:
DecArray = [1 2 4 69876];
cellstr(dec2hex(reshape(DecArray,[],1), 4));
ans =
'00001'
'00002'
'00004'
'110F4'
But as you see the outputs
1) always have the same number of digits, and
2) aren't broken into 2 Byte blocks
Is there any way to go from these results to the ones I described earlier without another loop?
5 Comments
Walter Roberson
on 22 Jan 2017
I dunno. It just seems unlikely to me that the data could vary between 16 and 32 bits on the same plot.
Accepted Answer
Stephen23
on 21 Jan 2017
Edited: Stephen23
on 21 Jan 2017
V = [1,2,4,69876];
L = log(16);
for k = 1:numel(V)
N = 4*(1+fix(log(V(k))/L/4));
S = sprintf('%0*X',N,V(k));
Z = sprintf('0x%c%c%c%c ',S)
end
Prints this in the command window:
Z =
0x0001
Z =
0x0002
Z =
0x0004
Z =
0x0001 0x10F4
Note: does not work for zero: add N = max(4,N)
More Answers (1)
Guillaume
on 21 Jan 2017
DecArray = [1 2 4 69876]';
h = arrayfun(@dec2hex, DecArray, 'UniformOutput', false);
cellfun(@(s) strcat('0x', cellstr(reshape([repmat('0', 1, mod(-numel(c), 4)), c], 4, [])')), d, 'UniformOutput', false)
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