insert matrix index to specific number

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ByoungYong Ryu
ByoungYong Ryu on 3 Mar 2017
Edited: Stephen23 on 3 Mar 2017
I have zeros matrix A = zeros(1,10);
and I want insert specific number to index range.
ex) index = [1 6 10]; value = [4 6];
I want return the matrix ans = [4 4 4 4 4 4 6 6 6 6];
How can I return this answer not using 'for';

Answers (3)

Andrei Bobrov
Andrei Bobrov on 3 Mar 2017
my small contribution
index = [1 6 10];
value = [4 6];
ii = zeros(index(end),1);
ii([1,index(2:end-1)+1]) = 1;
A = value(cumsum(ii));
  2 Comments
Jan
Jan on 3 Mar 2017
+1: I'd prefer this and guess, it is the fastest solution.
Walter Roberson
Walter Roberson on 3 Mar 2017
This assumes that index(1) is 1.
It is an interesting approach, though.

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Walter Roberson
Walter Roberson on 3 Mar 2017
A(index(1):index(end)) = repelem( value, [index(2)-index(1)+1,diff(index(2:end))]);

Stephen23
Stephen23 on 3 Mar 2017
Edited: Stephen23 on 3 Mar 2017
For MATLAB versions without repelem (pre R2015a):
>> index = [1 6 10]; value = [4 6];
>> cell2mat(arrayfun(@(d,v)repmat(v,1,d),diff(index),value,'Uni',0))
ans =
4 4 4 4 4 6 6 6 6
  2 Comments
Walter Roberson
Walter Roberson on 3 Mar 2017
Notice though that you output five 4's when the desired output is six 4's. The pattern appears to be that the first index gives a starting position number, that the next gives the ending position number of the first value, that the next after that gives the ending position number of the second value, and so on. The number of repeats of the first item is special, which is why I ended up using [index(2)-index(1)+1,diff(index(2:end))]
Stephen23
Stephen23 on 3 Mar 2017
Edited: Stephen23 on 3 Mar 2017
@Walter Roberson: thank you for fixing that strange inconsistency in the index definition. Applying your fix:
>> index = [1 6 10]; value = [4 6];
>> idx = [index(2)-index(1)+1,diff(index(2:end))];
>> cell2mat(arrayfun(@(d,v)repmat(v,1,d),idx,value,'Uni',0))
ans =
4 4 4 4 4 4 6 6 6 6

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