How can I solve this integral equation?
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Hello everyone, my name is Jose from Sevilla.
I have a function f(T) given by:
f(T)=a+bT+cT^2, where a,b and c are known numbers and T denotes Temperature.
Now I have this equation, where d is yet another constant:
I need to solve for T2, since T1 is also known. In fact, the only unknown here is T2.
I thought about using the trapz function, but I don't know how to include the T2 unknown. Any help will be greatly appreciated! (Important: I don't have the Symbolic Math Toolbox, so I can't do it symbolically. I don't have access to the Optimization Toolbox either, so fsolve and solve are ruled out, too).
Thank you!
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Answers (3)
Roger Stafford
on 12 Apr 2017
I would suggest utilizing a little calculus here:
integral of a+b*T+c*T^2 w.r. T from T = T1 to T = T2
is equal to:
I = a*(T2-T1)+b/2*(T2^2-T1^2)+c/3*(T2^3-T1^3)
or
c/3*T2^3+b/2*T2^2+a*T2-c/3*T1^3-b/2*T1^2-a*T1-I = 0
You have said everything is known except T2, so you can express T2 as the real solution (or solutions) to:
T2 = roots([c/3,b/2,a,-c/3*T1^3-b/2*T1^2-a*T1-I]);
2 Comments
Jose Lopez
on 12 Apr 2017
Thank you, since f(T) is always a polynomial your solution will work in my case withouth integrating f.
Never heard of root. Thank you again!
Roger Stafford
on 12 Apr 2017
You need to be prepared for multiple roots from 'roots'. Presumably just one of them will be the one you want. An n-th order polynomial always yields n roots even though some of them may be complex-valued. That is not a difficulty introduced by 'roots' or matlab. It is inherent in the statement of your problem.
Roberto
on 29 Apr 2017
1 Comment
Roger Stafford
on 30 Apr 2017
I disagree. ‘roots’ will still work here. The equation
f(T) = a + b*T + c*T^2 + d/T
is equivalent to the equation
c*T^3+b*T^2+(a-f(T))*T+d = 0
which can also be solved with ‘roots’ assuming f(T) is known. You will, however, get three solutions to this third degree equation.
Zeeshan Salam
on 1 Dec 2019
how i implement the integral function of this equation sin square 6 theta dtheta
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