Struct to double conversion
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I have 59 images in a file and when i am running it, it shows "59x1 struct" but i need to convert it into double format which i need it. Can anyone please help me to do that.
11 Comments
Stephen23
on 14 Apr 2017
Edited: Stephen23
on 14 Apr 2017
I know that you want a double array. But you have not answered my question about the dimensions that you want the double array to have. I will ask once more:
The images are (most likely) 3D. How many dimensions do you want the double array to have? Or, put another way, how do you want the images arranged relative to one-another?
Answers (2)
Saurabh
on 28 May 2023
To convert a struct of 59 images to a double format, you will need to loop over each image and convert it by calling the im2double() function. Here's some sample code:
% Assuming your struct of images is called "images"
num_images = length(images);
double_images = cell(1,num_images);
for i = 1:num_images
double_images{i} = im2double(images(i).data);
end
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Parag Jhunjhunwala
on 9 Jun 2023
Edited: Parag Jhunjhunwala
on 9 Jun 2023
There are 2 ways of converting an image to double format:
1. Using im2double() function:
double_images=[];
for i=1:length(images)
img = imread(images{i}); % read the image
double_images(i) = im2double(img); % convert the image to double
end
2. Using double() function:
double_images=[];
for i=1:length(images)
img = imread(images{i}); % read the image
double_images(i) = double(img); % convert the image to double
end
Both of these methods convert an image to a double-precision array, but the main difference is that im2double() function scales the output range to [0,1] while double() function keeps the original dynamic range of the input image.
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