Plot date and time

I have date and time values that I'd like to use for my XTick values. The data is in an array that has date, time and price. I would like to plot my price across multiple days and each time interval, 5 minute intervals. How can I set this up? Is it possible to set XTick to every 1.5 hours or every 18 ticks?
This is what I have right now but it doesn't accomplish what I want:
the array is 415x3 set like [date time price]
date = datenum(date,'mm/dd/yy');
time = datenum(time,'HH:MM');
count = length(time);
plot(price, count)
Thanks for your help!

Answers (1)

Thomas
Thomas on 29 Mar 2012
If you have date and time as cell's in Vectors date in format cell{mm/dd/yy} time in format cell{HH:MM:SS}
1) concatenate them
dt_time=[date time];
2) convert cell to mat
dt_time_new=cell2mat(dt_time);
3) convert to datenum here
final_time=datenum(dt_time_new,'mm/dd/yyHH:MM:SS');
plot(final_time,price)
datetick('x','mm/dd','keepticks') % or which ever format you want

7 Comments

Trader
Trader on 29 Mar 2012
Is there a way to do this if date and time are already in serial format?
Thomas
Thomas on 29 Mar 2012
Can you show an example of date time array
Trader
Trader on 30 Mar 2012
I am using the import() function to pull data from a .csv file and then assigning the values to a structure "f" after converting the dates to serial values
import = importdata(full_path);
% the first column (starting from the second row) is the trading days in format mm/dd/yyyy.
idate = import.textdata(2:end,2);
itime = import.textdata(2:end,3);
f.date = datenum(idate,'mm/dd/yy');
f.time = datenum(itime,'HH:MM');
% Create OHLC matricies
f.price_close=import.data(:,4);
Thanks again for you help!
Geoff
Geoff on 30 Mar 2012
That line f.time will not give you a sensible result. I tried this. You need to do:
f.time = mod(datenum(itime,'HH:MM'), 1);
Then you can use:
final_time = f.date + f.time;
Alternatively, you can do this (if you don't need to split date and time in the first place):
f.datetime = datenum( [idate ' ' itime], 'mm/dd/yy HH:MM');
Geoff
Geoff on 30 Mar 2012
Oh, actually you probably can't do my last suggestion cos your strings are gonna be in a cell array. You could use cellfun, but given that you are asking how to apply Thomas' answer to your code which is nearly identical, maybe you should stay away from cellfun for now! =)
Trader
Trader on 3 Apr 2012
Geoff - Could you give me your suggestion on how to use cellfun to accomplish this? I'm interested in learning.
KRUNAL
KRUNAL on 12 Aug 2014
Edited: KRUNAL on 12 Aug 2014
Thomas I tried using it. It says datenum failed for line 23
This is my code.
clc;
clear all;
orginf = '<filename>';
sheet = 'Sheet1';
for n =1:151
xlrange = ['C' num2str(n+1)];
a = xlsread (orginf,sheet,xlrange);
if a==1
range = ['E' num2str(n+1)];
range1 = ['F' num2str(n+1)];
range2 = ['S' num2str(n+1)];
[~,~,b] = xlsread(orginf,sheet,range);
c = xlsread(orginf,sheet,range1);
d = {datestr(c,'HH:MM:SS')};
dt_time = [b,d];
[~,~,mag] = xlsread(orginf,sheet,range2);
mag_new = double(cell2mat(mag));
dt_time_new=cell2mat(dt_time)
final_time=datenum(dt_time_new,'mm/dd/yyHH:MM:SS'); %line 23
plot(final_time,mag_new)
datetick('x','mm/dd','keepticks')
end
end
and my data in the various columns are as follows :
Stage Magnitude Date Time
1 -1 06/10/2012 17:56:50
1 -3 06/10/2012 17:59:33
2 -2 06/11/2012 8:52:45
2 -5 06/11/2012 8:52:46
3 -3 06/12/2012 9:11:37
3 -4 06/12/2012 9:55:56
3 -1 06/12/2013 9:57:46
4 -5 06/12/2013 10:47:49
4 -2 06/12/2013 10:48:08
4 -4 06/12/2013 10:50:35
5 -3 06/12/2013 7:47:43
5 -1 06/12/2013 8:15:30
5 -2 06/12/2013 8:16:04
I am trying to plot magnitude v/s date time. Please suggest me what is wrong with it ?

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Asked:

on 29 Mar 2012

Edited:

on 12 Aug 2014

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