Varargin - mistake in my example

Hi everyone, I wrote the following function:

function [x] = ingressi_arbitrari(varargin)

x=0;

for k=1:nargin

      x=x+1;

end

end

Why if I run a=ingressi_arbitrari([2 3]) in the command window, the result is a=1 instead of a=2 (I choose two input arguments)?

Thank you very much.

Answer 1

[Walter Roberson]

You only have one input argument, that happens to be length 2. If you had

a=ingressi_arbitrari([2 3], [7; 1; 8; 5])

then you would have two input arguments, the first length 2 and the second length 4

Answer 2

[Andrei Bobrov]

use:

ingressi_arbitrari(2,3)