Creating an ellipse plot with a for loop

For some reason my superellipse isn't shown in the figure when I run my code below in MatLab. I don't know where I went wrong, do I need to store the values in some way and then plot these values in the figure? Hope someone can help me out, thanks.

-Somehow the code underneath isn't shown correctly in the square on this website, sorry -

n=2;          
a=1;
b=1;
x0=0;  % x0,y0 ellipse centre coordinates
y0=0; 

for t=0:0.01:2*pi;
    if t < 0
        x=x0+(abs(cos(t)).^(2/a)) * a*-1*(abs(cos(t)));
        y=y0+(abs(sin(t)).^(2/b)) * b*-1*(abs(sin(t)));
    end

      if t == 0
          x=x0+(abs(cos(t)).^(2/a)) * a*0*(abs(cos(t)));
          y=y0+(abs(sin(t)).^(2/b)) * b*0*(abs(sin(t)));
      end

      if t > 0
          x=x0+(abs(cos(t)).^(2/a)) * a*1*(abs(cos(t)));
          y=y0+(abs(sin(t)).^(2/b)) * b*1*(abs(sin(t)));
      end
      figure(1)
      plot(x,y)
      grid on;
      grid minor;

end

Answer 1

[KSSV]

clc ; clear all ;
n=2;
a=1;
b=1;
x0=0;  % x0,y0 ellipse centre coordinates
y0=0;
figure(1)
hold on
for t=0:0.01:2*pi;
    if t < 0
        x=x0+(abs(cos(t)).^(2/a)) * a*-1*(abs(cos(t)));
        y=y0+(abs(sin(t)).^(2/b)) * b*-1*(abs(sin(t)));
    end
    if t == 0
        x=x0+(abs(cos(t)).^(2/a)) * a*0*(abs(cos(t)));
        y=y0+(abs(sin(t)).^(2/b)) * b*0*(abs(sin(t)));
    end
    if t > 0
        x=x0+(abs(cos(t)).^(2/a)) * a*1*(abs(cos(t)));
        y=y0+(abs(sin(t)).^(2/b)) * b*1*(abs(sin(t)));
    end

      plot(x,y,'.r')
      grid on;
      grid minor;
  end