The loop is causing time out so i want to convert it to matrix operations.

I ave re written my doubts so please consider it now,

for i = 2 : LenRxDiv
  UsedAnt = currAnt(i-1);
  %UsedAnt = currAnt(1:LenRxDiv);
  StartTime = currTime(i-1);
  %StartTime[1:LenRxDiv] = currTime(1:LenRxDiv);
  %check for intersection with CQI
  IntersLen = min([(ActTimeStop - StartTime) (currTime(i) - ActTimeStart) repmat((currTime(i) - StartTime),NumActReg,1) (ActTimeStop - ActTimeStart)], [], 2);
  %IntersLen[1:LenRxDiv] = min([(ActTimeStop[1:LenRxDiv] - StartTime[1:LenRxDiv]) (currTime[1:LenRxDiv] - ActTimeStart[1:LenRxDiv]) repmat((currTime[1:LenRxDiv] - StartTime[1:LenRxDiv]),NumActReg[1:LenRxDiv],1) (ActTimeStop[1:LenRxDiv] - ActTimeStart[1:LenRxDiv])], [], 2);
  UtilHSDPA(UsedAnt) = UtilHSDPA(UsedAnt) + sum(IntersLen(IntersLen>0));
  UtilAll(UsedAnt) = UtilAll(UsedAnt) +  currTime(i) - StartTime;
end

These are the values of above code:

when i = 2

LenRxDiv : 1*1 double = 725590
UsedAnt :1*1 double = 2
IntersLen : 120936 * 1 double = -5238 -88277/3 .... ..... ..... .....
StartTime :1*1 double = 2046467740
ActTimeStop : 120936 * 1 double = 2046462502 .... .... ...... .....
ActTimeStart : 12093 * 1 double = 2046462502 .... .... .... ....
CurrTime(i) : 725590 * 1 double = 20464627740 ..... .... .....
NumActReg : 1 * 1 double = 120936
UtilHSDPA(UsedAnt) : 1 * 4 double = 0 0 0 0

so now could someone please explain how can remove the loop from above code since its causing timeout and can it be converted into matrix manipulation.

[dpb]

%check for intersection with CQI
IntersLen=min([(ActTimeStop-StartTime) (currTime(i)-ActTimeStart) ...
          repmat((currTime(i)-StartTime),NumActReg,1) ...
         (ActTimeStop-ActTimeStart)], ...
[], 2);

Why are you replicating the same value NumActReg times just to take the minimum???? One copy is as good as as 120,936 of 'em!!! That alone should help noticeably I'd think...

IntersLen=min([(ActTimeStop-StartTime) (currTime(i)-ActTimeStart) ...
               (currTime(i)-StartTime) (ActTimeStop-ActTimeStart));

[dpb]

Also what is array(?) currAnt? You say if loop index i=2 that UsedAnt=2 which would be the first element in currAnt so it must start with initial value of 3. Is it just 3:SOMEBIGNUMBER or some other indexing scheme/ordering?

What is the expected output?

[dpb]

And another issue--

ActTimeStop-StartTime(i-1) is the same as ActTimeStop-currTime(i-1) since

StartTime = currTime(i-1);

in the line preceding. BUT, the loop on i runs over 2:LenRxDiv --> 2:725,590 while you state size(ActTimeStop)=12,0936,1. 725590/120936=5.9998 so those two are hugely disparate sizes and you'll blow up the loop way before you can finish it even if it weren't so large.

The conclusion is you've not really worked out the details of what it is you're actually trying to compute; the numbers just don't match up with what you're trying to compare.

[MSDataSpl1]

I am using repmat in order to equalize the dimension of all the matrices used to find minimum value using min().So can you suggest any substitution for this line,

IntersLen=min([(ActTimeStop-StartTime) (currTime(i)-ActTimeStart) ...
        repmat((currTime(i)-StartTime),NumActReg,1) ...
       (ActTimeStop-ActTimeStart)], ...
[], 2);

the expected output is the time interval difference between the traces and it is getting populated in

 UtilHSDPA(UsedAnt) = UtilHSDPA(UsedAnt) + sum(IntersLen(IntersLen>0));
  UtilAll(UsedAnt) = UtilAll(UsedAnt) +  currTime(i) - StartTime;

[MSDataSpl1]

Even when i am using the change you mentioned

IntersLen=min([(ActTimeStop-StartTime) (currTime(i)-ActTimeStart) ...
             (currTime(i)-StartTime) (ActTimeStop-ActTimeStart));

then i am getting the error,

Dimensions of matrices being concatenated are not consistent.

[MSDataSpl1]

I want to find the minimum value of the matrices so i am using min function but the problem is the dimension of matrix should be same so i am using repmat but it causing timeout when used for multiple iterations, so is there any substitut for repmat