I want to vary how much of a plane is filled with the angle of the plane with the horizontal, any help?

I am running an experiment and currently have a 300x300 zeros matrix and the lower half filled with ones to get a half-plane image. Now I want to 'tilt' this plane with different angles to see how this changes what I am testing. Is there a code I could use to do this?

Any more questions on this (cause I know this could be a bit confusing) please just drop a comment or send me a message.

[José-Luis]

Well, what have you tried so far?

[Jan]

An angle is not enough for tilting, but you need a center of rotations also: Is it at [150.5, 150.5]?

[Daniel Gray]

Yes sorry, because of it being a matrix, we'll just make the centre of rotation [150 150]

Answer 1

[Jan]

x = 1:300;
y = 1:300;
m = atan(30 * pi / 180);  % 30 deg
k = bsxfun(@plus, m * (x - 150), y.' - 150) > 0;  % Rotate around [150,150]
imagesc(k);

Since R2016b this is simpler:

k = (m * (x - 150)) +  (y.' - 150) > 0;

[Daniel Gray]

Looks great, just ran it with 45 degrees and expected it to reach the corners. I guess my question is how are the angles actually defined?

[Jan]

Can the readers know, how the angles are defined in your case? The question was "I want to 'tilt' this plane with different angles".

[Daniel Gray]

Sorry yes I should have been more clear. I wanted the angle to be defined as between the horizontal across the centre and the new 'tilted plane' about the centre of rotation. If that doesn't make sense I can send you a diagram

[Jan]

Well, in the code I've posted I used 30 deg as angle. You can replace the angle by a variable:

YourAngle = 17.3;  % deg 
m = atan(YourAngle * pi / 180);  % 30 deg

But if you ran the code with 45 deg, you have done this already. Therefore I do not understand, what the problem is now. What is the difference between the result my code creates and the wanted matrix?