Filling A matrix with characters in a loop

Hello i want to fill a matrix with characters in a loop, for example i want to have a variable 'n' which my loop starts with 1 and ends with 'n' and fill a matrix with one column and 'n' rows with characters like 's' in some rows in a condition and 'us' in another condition, in the other word; i dont know how i can fill a char matrix in a loop

[Image Analyst]

Will the conditions change once you're into the loop, or is the condition the same for the whole loop? Is it a 2D matrix? If so, which column do you want to assign?

Answer 1

[Walter Roberson]

If you need to fill some positions with 'us' then you need a string at each position rather than a character . You will need to use cell arrays for that, or else use a matrix with one higher dimensions together with blank padding.

for col = 1 : n
  if rand() <= 0.8  %the main condition
    YourMatrix(:,col) = 's';  %fill this column
  else   %the alternate condition
    YourMatrix(:,col) = 'u';  %alternate fill
  end
end

[sohrab]

thank you for your helpful answer, now i have another problem, i want to have a matrics which one of its columns has strings and another columns are numbers, something like this:

1 0.3565 st

2 0.6456 ust

how could i have something like this? the third column of this matrics is that matrix which i asked you before

[Walter Roberson]

The only way to do this is to use a cell array.

YourMatrix = num2cell(rand(n,2)); %two columns of numbers in cell

for row = 1 : n

if rand() <= 0.8 %the main condition

YourMatrix{row,3} = 'st'; %fill this entry

else %the alternate condition

YourMatrix{row,3} = 'ust'; %alternate fill

end

end

Notice the use of {} instead of ()