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vincenzo
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Derivative in function handle

Asked by vincenzo
on 11 Sep 2017
Latest activity Commented on by James Tursa
on 12 Sep 2017
f=@(x) x + log(x);
f1=diff(f)
f2=diff(f1)
I want to assign first derivative of 'f' to 'f1', and second derivative for 'f1' to 'f2' But i have this error "Undefined function 'diff' for input arguments of type 'function_handle'". How to fix? Thanks

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2 Answers

Answer by James Tursa
on 11 Sep 2017
Edited by James Tursa
on 11 Sep 2017

E.g., if you want function handles you could get at them with the symbolic toolbox
>> syms x
>> f = @(x) x + log(x)
f =
@(x)x+log(x)
>> f1 = eval(['@(x)' char(diff(f(x)))])
f1 =
@(x)1/x+1
>> f2 = eval(['@(x)' char(diff(f1(x)))])
f2 =
@(x)-1/x^2
If you plan on feeding vectors or matrices etc to these function handles, then you could wrap the expressions appropriately with the vectorize( ) function. E.g.,
>> f1 = eval(['@(x)' vectorize(char(diff(f(x))))])
f1 =
@(x)1./x+1
>> f2 = eval(['@(x)' vectorize(char(diff(f1(x))))])
f2 =
@(x)-1./x.^2

  2 Comments

No need for the eval()
syms x
f = @(x) x + log(x)
f1 = matlabFunction( diff(f(x)) );
f2 = matlabFunction( diff(f1(x)) );
James Tursa
on 12 Sep 2017
@Walter: +1

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Answer by José-Luis
on 11 Sep 2017
Edited by José-Luis
on 11 Sep 2017

If you're gonna do this numerically, you need to specify an interval in which to evaluate. Note that diff doesn't really give the derivative, but I'll stick to your nomenclature.
limits = [1,10];
f = @(interval) (interval(1):interval(2)) + log(interval(1):interval(2));
f1 = diff(f(limits));
f2 = diff(f1);
You could also do it symbolically but I can't help you there because I don't have the symbolic math toolbox.

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