How to solve this integral?

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N/A
N/A on 30 Sep 2017
Edited: Walter Roberson on 2 Oct 2017
Dear all,
I must to solve this double integral:
function = exp(0.5*i*pi*(u^2 + v^2))*du*dv
u_min = (p - v*cos(alfa))/sin(alfa)
u_max = inf
v_min = q
v_max = inf
p, q and alfa are constant, but u_min is a function of the external variable v.
I tried to solve it with integral2 or other functions, but I don't understand how to manage at the same time u_min and u_max and v_max, that are infinite.
  1 Comment
Torsten
Torsten on 2 Oct 2017
Your integral does not exist since your function does not approach zero as u and v go to infinity.
Best wishes
Torsten.

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