Creating a matrix with variables

Hi Folks,

So I'm trying to create my own version of a continuous least squares. Here's a picture of what I'm attempting to do.. (these notes were taken in class, the integrals should be attached to all elements of the matrix, sorry)

I figured I would approach this problem by creating the first row of my matrix which was coded as

 syms('x','a','b','n')
 f = sqrt(x); 
 A = [int(x.^(n),a,b) int(x.^(n+1),a,b) int(x.^(n+2),a,b)];
 b = [int(x.^(n)*f,a,b) int(x.^(n+1)*f,a,b) int(x.^(n+2)*f,a,b)];
 N = 2;

And tested with n=0, which gave me the results I wanted. Now to use a for loop to create the rest of the matrix. I want n grow by 1 for each loop until I hit N, and I also want to add another row to my matrix each time my n goes up. I'm a simple man and figured the following code would work, but I keep getting the error:

Index exceeds matrix dimensions.

Error in sym/subsref (line 814) R_tilde = builtin('subsref',L_tilde,Idx);

when I run this

 for i=1:N
     A(i,:) A(i+1,:);
     n = n+1;
 end

Any advice, tips, tricks, etc would be appreciated!

Answer 1

[Kian Azami]

I think you can easily do this by saving your A variable to a new variable like B and a small change in your for loop:

   n = 1;
  for i=1:N
     B(i,:) = A;
     n = n+1;
  end

Now each time the loop is run (which for your case is N = 2) the A variable is calculated by the new n and it will assign the A to a new raw of B.