Eigen value eigen vectors in matlab
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I want to solve this question.I'm going to atteched my code but I don't know this code is true.
if true
clc;
clear all;
A=[4 -5;-2 1];
Eig=eig(A)
F=poly(A)
[V,D]=eig(A)
V1=V(:,1)
V11=V1/V(1,1)
end
1 Comment
Walter Roberson
on 21 Jan 2018
What are you doing with the Eig and F values you calculate?
I do not see any initial value problem in the question presented: it gives the initial value. Initial value problems require that information about the original condition is missing and needs to be calculated, which is not the case here.
Accepted Answer
Birdman
on 21 Jan 2018
Your approach is nice, but not enough of course. First, you need to construct a differential equation for your second question. Third question comes with the second one. The answer for your first question is included in this line:
[V,D]=eig(A)
Full solution may look like as follows:
%%1st
A=[4 -5;-2 1];
[V,D]=eig(A)
%%2nd
syms x1(t) x2(t)
x0=[2.9;2.6];
eq1=diff(x1,t)==A(1,:)*[x1(t);x2(t)];
eq2=diff(x2,t)==A(2,:)*[x1(t);x2(t)];
solx=dsolve([eq1 eq2],[x1(0)==2.9 x2(0)==2.6]);
x1=solx.x1
x2=solx.x2
%%3rd
t=subs(t,0:0.1:1);
x1=subs(x1,t);
x2=subs(x2,t);
plot(t,x1,'o',t,x2,'-*')
2 Comments
More Answers (2)
johnson wul
on 23 Jul 2019
Nice that. is this formular for eigenvector:
plot(t,x1,'o',t,x2,..,t,x10, '-*')
have been used to for square matrix 10*10 for example if some one want to plot differents eigenvectors?
And how to plot in 3 dimensions the previous eigenvectors? just a step
0 Comments
mercy charles
on 19 Feb 2022
%%1st
A=[4 -5;-2 1];
[V,D]=eig(A)
%%2nd
syms x1(t) x2(t)
x0=[2.9;2.6];
eq1=diff(x1,t)==A(1,:)*[x1(t);x2(t)];
eq2=diff(x2,t)==A(2,:)*[x1(t);x2(t)];
solx=dsolve([eq1 eq2],[x1(0)==2.9 x2(0)==2.6]);
x1=solx.x1
x2=solx.x2
%%3rd
t=subs(t,0:0.1:1);
x1=subs(x1,t);
x2=subs(x2,t);
plot(t,x1,'o',t,x2,'-*')
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