Divide vector of coordinates into even intervals.

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Hi!
I have a long vector of longitude and latitude coordinates representing one bus route. Though the distance between each following pair of coordinates is different through the vector. I want to generate new longitude-latitude coordinates so that I have lots of intervals with same length.

Accepted Answer

Jim Riggs
Jim Riggs on 22 Feb 2018
Based on your description of the problem, this is what I would do:
Given a vector of lat/lon positions which represents one route, where the distance between points is not evenly spaced. I want to divide this route into N evenly spaced distances.
In order to interpolate on distance, you need to create the distance vector that corresponds to the lat/long vector. Compute the distance from the start of the route for each lat/lon point. E.g. d1 = zero, d2 = the distance from pt1 to pt2. d3 = d2 + distance from pt2 to pt3, etc. This vector is monotonically increasing from zero to the total route length.
Now you interpolate the total distance vector based on your desired distance spacing, then use that to locate the corresponding position in the lat/lon vector. The corresponding point will be bounded by the same index values, and have the same fraction displacement between the bounding values.
  1 Comment
Hampus Alfredsson
Hampus Alfredsson on 23 Feb 2018
Yes, I managed to solve the problem by interpolation and some if-restrictions for certain intervals. Thank you

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More Answers (1)

KSSV
KSSV on 22 Feb 2018
You need to have a look on interpolation......Read about interp1.
  2 Comments
Hampus Alfredsson
Hampus Alfredsson on 22 Feb 2018
Yes, interpolation works to begin with. But whenever the direction of coordinates become negative(the bus is driving on a road that is slightly back towards its starting point), the interp1 become wrong.
Stephen23
Stephen23 on 22 Feb 2018
@Hampus Alfredsson: interpolation works with negative values just as well as it does positive ones. Please make a new comment and upload your code by clicking the paperclip button.

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