Indexing Results of a For Loop When the Input Comes from a Function
1 view (last 30 days)
Show older comments
I just started using functions as loop inputs and never had to index the results before. My goal is to store the results of rpf_cba and vpf_cba into a matrix. Here's what I'm working with:
for i=0:h:11940
[r_step_cba, v_step_cba] = RK4_single_step(mu, rpf_cba, vpf_cba, h);
i = i+h;
rpf_cba = r_step_cba;
vpf_cba = v_step_cba;
semi_cba = -(norm(rpf_cba)*mu)/((norm(rpf_cba)*norm(vpf_cba)^2)-(2*mu)).*semi_store
i = i+1;
end
I'm quite used to indexing loop results and tried all of the usual methods (preallocation, index variable, etc.) but after spending a couple of days on this, I cannot figure out what's going on. The most common error I get is this:
In an assignment A(I) = B, the number of elements in B and I must be the same. Error in Exam_2_Question_4 (line 60) rpf_cba(i) = r_step_cba;
which makes me think the loop and function aren't looking in the same place for results to actually index. Alternatively, if I take the semi_ones variable and multiply it by r_step_cba, I get a 'Matrix dimensions must agree' error. If anyone has some experience with this, I'd be grateful for some advice. Also, let me know if more code is needed; the input function is pretty big so I didn't want to clutter things from the start. Thank you very much!
0 Comments
Accepted Answer
Abraham Boayue
on 11 Mar 2018
[r_step_cba, v_step_cba] = RK4_single_step(mu, rpf_cba, vpf_cba, h)
for i = 0:h:11940
i = i+h;
rpf_cba = r_step_cba;
vpf_cba = v_step_cba;
semi_cba = (norm(rpf_cba)*mu)/((norm(rpf_cba)*norm(vpf_cba)^2)-(2*mu))*semi_ones;
i = i+1;
end
2 Comments
Abraham Boayue
on 11 Mar 2018
Try to separate your comments from your code. It makes it difficult to understand the problem that you are having.
More Answers (1)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!