Bubble sort that stops running when sorted

I am having trouble figuring out how to get my bubble sort program to end when it is fully sorted.

    % %Bubble Sort V3_C%
clear all;clc
% Generate 10 integer random numbers
range = [1 10];
total_num = 10;
index = 1:total_num;
pause_sec = 0.01;
num = randi(range,1,total_num);
nums = num;
l_num = length(num);
end_ind = 1;
for j = 1:(l_num - 1)
    end_ind = end_ind+1
    for i = l_num:-1:end_ind
        if nums(i) > nums(i-1)
            tmp = nums(i);
            nums(i) = nums(i-1);
            nums(i-1) = tmp;
        end
        home
        fprintf('j = %4i i = %4i \n' ,j,i)
        fprintf('\n')
        prtTable02(num,nums)
        figure(1)
        bar(nums)
        hold on
        bar([i,i-1],[nums(i),nums(i-1)],'r')
        hold off
        pause(pause_sec)
    end
end
clc;home
fprintf('end \n')
prtTable02(num,nums)

This is the function prtTable02(num,nums)

   function prtTable02(num,nums)
table = [num;nums];
fprintf('    num    num sorted\n')
fprintf('%5i   %5i \n',table)
pause(.1)
end

Answer 1

[James Tursa]

Typically you have a variable that keeps track of whether you did a swap or not in your most recent loop. E.g.,

    did_a_swap = 0;
    for i = l_num:-1:end_ind
        if nums(i) > nums(i-1)
            tmp = nums(i);
            nums(i) = nums(i-1);
            nums(i-1) = tmp;
            did_a_swap = 1;
        end
          :
    end
    if( ~did_a_swap )
        break; % didn't do a swap, so everything is sorted. Break out of outer loop.
    end

[Cameron Feldman]

Perfect, thank you!