# find the intersection point between 2 plane in matlab

2 views (last 30 days)
ha ha on 13 May 2018
Edited: ha ha on 13 May 2018
Let's say I have: the set of 3D data point (xi,yi,zi) contains around 10,000 points located in plane L
I also have : plane M which is specified by normal vector n , and point A(xA,yA,zA). How to find the intersection point between 2 plane L & M?

ha ha on 13 May 2018
Edited: ha ha on 13 May 2018
Plane L contains 10,000 points in 3D space OXYZ
Plane M contains (normal_vector & center_point). Firstly, finding the perpendicular distance of each point in plane L to the plan M. Example: 10,000 distance corresponding to 10,000 points.
Then check the condition to the Plane M. If the distance < distance_threshold. Example: 1cm or 5mm ====> then, choose those point satisfying that condition only

Ameer Hamza on 13 May 2018
For plane L find a normal to that plane using this FEX submission. This will give you a normal and a point on the plane L. Since you already have a normal and point to plane M, use another FEX submission to calculate their intersection.
Ameer Hamza on 13 May 2018
Edited: Ameer Hamza on 13 May 2018
If you just want to get 1000 points which lie on the line of intersection and plane L. Then you just need to sample the line of intersection. One example
p = [1 2 3]; % point of intersection returned by 'plane_intersect'
dir = [0.2 0.6 0.6]; % direction of intersection returned by 'plane_intersect'
t = (0:0.1:100)'; % to get 1000 samples
points = p.*(1-t)+(p+dir).*t; % p and dir must be row vectors
If you want points that lie on the line of intersection and also belongs to the initial dataset (xi, yi, zi) for plane L, then it is highly unlikely that any of that point will precisely lie on the line of intersection.
ha ha on 13 May 2018
Ok, thank @Ameer Hamza for providing me the idea.