y = imread(file1, 'BackgroundColor', [1 1 1]); WHAT DOES IT DO?
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I am getting an error in this line as:
Error using strfind
Input strings must have one row.
Error in getFileFromURL (line 8)
if (strfind(filenameIn, '://'))
Error in imread (line 327)
[isUrl, filename] = getFileFromURL(filename);
Error in oooo (line 63)
y = imread(I, 'BackgroundColor', [1 1 1]);
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Answers (2)
dpb
on 26 May 2018
doc imread
Read image from graphics file
Syntax
A = imread(filename)
A = imread(filename,fmt)
A = imread(___,idx)
A = imread(___,Name,Value)
...
Description
A = imread(filename) reads the image from the file specified by filename, inferring the format of the file
from its contents. If filename is a multi-image file, then imread reads the first image in the file.
A = imread(filename,fmt) additionally specifies the format of the file with the standard file extension indicated
by fmt. If imread cannot find a file with the name specified by filename, it looks for a file named filename.fmt.
...
A = imread(___,Name,Value) specifies format-specific options using one or more name-value pair arguments,
in addition to any of the input arguments in the previous syntaxes.
...
Ergo, the first argument must be a valid filename string; you've passed what looks to be an array, I.
6 Comments
SURILA GUGLANI
on 27 May 2018
1 Comment
Walter Roberson
on 27 May 2018
After you do
I = imread('Frame 0001.png') And later in the code used as...
then I is the content of Frame 0001.png , and is not a file name.
You would need something like
filename = 'Frame 0001.png';
I = imread(filename);
y = imread(filename, 'BackgroundColor', [1 1 1]);
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