How can I get subscript instead in indices from sort() ??

How can I get subscript instead in indices from

sort(mat(:));

Script:

%%Creation of 'mat'
mat = magic(100);
for i=1:100*100
  mat(mat>(100*i-100) & mat<=100*i)=i;
end

[~,idx] = sort(mat(:));

%%I dont want to use 'for' loop. I.e.,
for i=1:length(idx)  % I want to avoid for loop
[I(i),J(i)] = ind2sub(size(mat),idx(i));
end

I tried 'arrayfun' also but it is taking more time then for loop

 [I2,J2] = arrayfun(@(x) ind2sub(size(mat),x),idx);

[Fangjun Jiang]

mat(:) turns mat() into a column vector. No point to get indices anyway.

Answer 1

[jonas]

ind2sub accepts multiple indices as input. It's right there in the first example of the doc.

IND = [3 4 5 6]
s = [3,3];
[I,J] = ind2sub(s,IND)

[JAI PRAKASH]

OMG what a silly question I asked.

Thanx for ur exact help