Replacement for for loops
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Dhananjay Mishra
on 12 Oct 2018
Commented: Star Strider
on 12 Oct 2018
Hello everyone. I want to construct an array of data which will contain values like below example. Any suggestions on how to do this without using for loop will be very helpful. Thank you!
A = zeros();
x1 = 1
for u = -1:1:1
for v = -1:1:1
A(x1) = exp((-1i*(u-v).^2)/2);
x1 = x1+1;
end
end
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Accepted Answer
Star Strider
on 12 Oct 2018
Try this:
[U,V] = meshgrid(-1:1);
Am = exp((-1i*(U-V).^2)/2);
A = Am(:).';
It produces the same output as your code.
2 Comments
Star Strider
on 12 Oct 2018
As always, my pleasure.
I cannot understand what you want to do. If your code produces the result you want, just leave it as is. I doubt it can be vectorised.
Also, there are too many parentheses in your ‘value’ assignment, so it throws an error. I eliminated one left parenthesis to make it work:
value(x1,y1) = exp(-1i*((u-x)^2 + (v-y)^2))
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