Fastest way to create N by 1 matrix which contain lots of zero without using for loop

1 view (last 30 days)
I want to express n x 1 matrix, X
X = [ a; a; a; a; b; 0; 0; 0; b; 0; 0; 0; (...) b; 0; 0; 0; b; 0; 0; 0; c; c; ] ("b; 0; 0; 0;" block is repeated N times)
What I first design is that:
A = a * ones(4,1) ; B = zeros(4,1); B(1) = b ; C = c * ones(2,1); X = [ A ; B ; B ; (...) B ; B ; C ] ;
But the problem is that I cannot set a number of center block. How can I code it?
Thanks in advance :D

Accepted Answer

OCDER
OCDER on 12 Oct 2018
a = 1;
b = 2;
c = 3;
N = 10;
D = [repelem(a, 4, 1);
repmat([b; 0; 0; 0], N, 1);
repelem(c, 2, 1)];

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!