Averaging values within bins
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Hi,
I have the two arrays x and y (attached), which I plot with plot(x,y). This is creating "bins" of width 5:
What is the fastest way to average the values within each such bin, such that we end up with one value/bin, especially if we don't want to pre-define bin width?
Thanks
3 Comments
Stephen23
on 28 Oct 2018
"Would the histogram function help nevertheless?"
Yes, because they can also return the indices.
Answers (2)
Bruno Luong
on 28 Oct 2018
load('y.mat')
load('x.mat')
plot(x,y)
edges = (0:5:50);
[~,~,loc]=histcounts(x,edges);
meany = accumarray(loc(:),y(:))./accumarray(loc(:),1);
xmid = 0.5*(edges(1:end-1)+edges(2:end));
figure
plot(x,y)
hold on;
plot(xmid,meany,'r')
2 Comments
AnnieLieseMari
on 13 Jun 2022
Hi there!
I'm working with a very similar data set and need some help with my code. I know this was posted and answered a while ago, but I would really appreciate the help.
After using the same code you provided, but with my data set and edges of (4.25:0.5:17.75), I am getting an error saying "First input SUBS must contain positive integer subscripts."
I have a data set of x and y values that is upwards of 2000+ data points. It's super big and when I zip it, the Help Center is still saying it's too big. Please let me know if you'd like me to provide a sample of maybe 20 or so data points to help out.
I think the main reason this is happening is that my data has NaN values in it. Though, I'm not sure how to remove those. Of course, if I remove the x values, I have to preserve the y values so the other pairs still match up.
Bruno Luong
on 13 Jun 2022
Simply remove the bad data:
keep = isfinite(x) & isfinit(y);
x = x(keep);
y = y(keep);
... do the rest
Make sure the extrem edges cover entirely your data.
Steven Lord
on 28 Oct 2018
Do you want to use histogram or histcounts to bin the data, or are you looking for something more of a moving average, where the value of the averaged signal at a particular time is the mean of the data for that time and some data points before and after that time? If the latter, see movmean.
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