How to get the values of f at different x

how can I get f(k+1) reference to values of x, although if I remove range of x, I will get the answer interms of x but I need the values not in variable forms. Here is the code

syms x

P(1)=x^0;

P(2)=x;

for n=1:d

P(n+2)=expand(((2*n+1)/(n+1))*x*P(n+1)-(n/(n+1))*P(n));

end

for k=0:d

a=0;b=1;N=6;

x = a:0.1:b;

f(k+1)= exp(x).*P(k+1); % how can I get this reference to values of x

end

Answer 1

[Yasasvi Harish Kumar]

Try using the subs command to substitute values of x in your expression.

syms x

P(1)=x^0;

P(2)=x;

for n=1:d

P(n+2)=expand(((2*n+1)/(n+1))*x*P(n+1)-(n/(n+1))*P(n));

end

for k=0:d

f(k+1)= exp(x).*P(k+1);

a=0;b=1;N=6;

x = a:0.1:b;

t(k+1) = subs(f(k+1),x); % Actual value

end

[Kazeem Issa]

It doesn't work/run using t(k+1)

Regards