Using inequalities to compare arrays

Hello I am working on a code that will determine if data is within or beyond standard deviations of a particular curve. I currently cannot get to the point where I can alert a user via email because my if statement is comparing two arrays rather than two numbers.

%Define Variables
Time = table2array(SampleDataOutput(:,1));
Temp = table2array(SampleDataOutput(:,2));
CowA = table2array(CowADataOutput(:,2));

%Set Tolerances based on Sample
HighTolerance = Temp + std(Temp);
HighTolerance2 = Temp + (2*std(Temp));
LowTolerance = Temp - std(Temp);
LowTolerance2 = Temp - (2*std(Temp));


%Plot Cow A against Tolerances
figure(1)
plot(Time,Temp,'color','green')
hold on 
plot(Time,HighTolerance,'color','yellow')
plot(Time,HighTolerance2,'color','red')
plot(Time,LowTolerance,'color','yellow')
plot(Time,LowTolerance2,'color','red')
plot(Time,CowA,'color','black')
hold off
title('Cow A from 5:30AM to 11:00AM')
xlabel('Time (15-minute increments)') 
ylabel('Temperature (Degrees Fahrenheit)') 
legend ('Green=Ideal', 'Yellow=Warning','Red=Sick Cow')

% If-Then Cow A - Alerts
if CowA > HighTolerance && CowA < HighTolerance2  % THIS IS NOT WORKING BECAUSE INEQUALITY FOR TWO ARRAYS
    sendmail('[e-mail]','Cow A Health-FRS', ...
    'Cow A should be watched, please look at your updated site to see more details.');
end
if CowA > HighTolerance2
    sendmail('example.com','Cow A Health-FRS', ...
    'Cow A seems to have a fever based on our readings. Please see your updated site for more details asap!');
end

Answer 1

[Image Analyst]

What are the sizes (rows and columns) of CowA and HighTolerance2?

Do you want to enter the "if" if ALL of them are true, or if ANY of them are true?

Use all() or any() to compare arrays.

[Wyatt Jankauskas]

both are 1 column and 23 rows.

I want to send an email when the CowA temp is higher then the tolerances and a separate message when it is inbetween the tolerances. As an example for CowA based on this picture the code should mark it as good because it is within these bounds, but for CowC i want it to send a notification via email. Does this make sense?

[Wyatt Jankauskas]

[Image Analyst]

No it doesn't make sense (to me). Those are two vectors, and some elements are between the tolerances and some are not. So in that case, do you want to send an email or not? Surely you don't want to send an email for every element of the vector that is in between the tolerances. You probably don't want to send dozens of emails. You probably only want to send one, unless you're capturing data over a long time, like hours, and want to send one every time based on the latest measurement rather than the whole vector.

[Wyatt Jankauskas]

Okay i see what you mean. is there a way that i can say

“if 5 points are beyond hightolerance send mail”?

[Image Analyst]

Yes:

mask = CowA > HighTolerance & CowA < HighTolerance2;  % Use single & NOT double &&
if sum(mask) > 5
    % Send mail if more than 5 elements are in the tolerance range.
    sendmail(............)
end

[Wyatt Jankauskas]

Alright, I think I am in the right direction! Do you know why it would be telling me that when saying:

mask = CowA > HighTolerance & CowA < HighTolerance2;

That the & might not be used? That is the only thing giving me an error now

[Image Analyst]

If CowA is a vector, and HighTolerance and HighTolerance2 are scalars, or vectors the same size and shape as CowA, it should work. What does this show:

whos CowA
whos HighTolerance 
whos HighTolerance2

[Wyatt Jankauskas]

Name Size Bytes Class Attributes

CowA 23x1 184 double

Name Size Bytes Class Attributes

HighTolerance 23x1 184 double

Name Size Bytes Class Attributes

HighTolerance2 23x1 184 double

[Wyatt Jankauskas]

Undefined function or variable 'mask'.

Error in frs3 (line 116)

mask == CowA >= HighTolerance & CowA <= HighTolerance2;

[Wyatt Jankauskas]

Oops I took out the double == and it works! Thanks so much!!!