find the differences between two funtions

I have two functions as follows:

v=g*b/(2*pi*(1-nu)).*x.*(x.^2-y.^2)./(x.^2+y.^2).^2;

P=-g*b/(2*pi*(1-nu)).*(x./(x.^2+(y+zi).^2)-2.*x.*y*(y+zi)./(x.^2+(y+zi).^2).^2)
g=46e9;
b=0.2556e-9;
nu=0.33;
zi=0.155e-9;
y=1e-8;
x=2e-9:1e-10:2e-7;

I want to find that at what amount of x, the dfference between v and p is equal to 0.2

Answer 1

[Sreelakshmi S.B]

You can try the following code:

g=46e9;
b=0.2556e-9;
nu=0.33;
zi=0.155e-9;
y=1e-8;
x=2e-9:1e-10:2e-7;

v=@(x) g*b/(2*pi*(1-nu)).*x.*(x.^2-y.^2)./(x.^2+y.^2).^2;
P=@(x) -g*b/(2*pi*(1-nu)).*(x./(x.^2+(y+zi).^2)-2.*x.*y*(y+zi)./(x.^2+(y+zi).^2).^2);

%creating a function handle for calculating diff
diff = @(x) v(x) - P(x);

allZeros = [];

for x=2e-9:1e-10:2e-7
    if(abs(round(diff(x),1))==0.2)
        allZeros = [allZeros,x];
    end
end

%allZeros will have all values of x for which diff is 0.2

However the values you've specified for x won't give you any values with diff. as 0.2 since the step size for x is too large.You can try observing where the diff is crossing over 0.2 and try reducing the step size.You can also plot the graph for 'P-v' and observe where it crosses 0.2.

[madhan ravi]

Naming a variable diff is not recomended.