remove all the spaces from a string.

I have a string:

Pre_CRC = '[1 0 1 0 1 1 1 1 0 1 0 1 0 0 1 0]'

I need to convert this into a string to convert it into a unintialized binary number.

A = [msg_FCS(1,16385),msg_FCS(1,16386),msg_FCS(1,16387),msg_FCS(1,16386),msg_FCS(1,16387),...
    msg_FCS(1,16388),msg_FCS(1,16389),msg_FCS(1,16390),msg_FCS(1,16391),msg_FCS(1,16392),...
    msg_FCS(1,16393),msg_FCS(1,16394),msg_FCS(1,16395),msg_FCS(1,16396),msg_FCS(1,16397),...
    msg_FCS(1,16398),msg_FCS(1,16399),msg_FCS(1,16400)];
Pre_CRC = (mat2str(A));

Trim_CRC = zeros(1,16);
Trim_CRC_Counter = 1;
    for dd = 1:length(Pre_CRC)

          if (isspace(Pre_CRC(:,dd)) == 1)
              Pre_CRC(:,dd) = [];
          else
              Pre_CRC(1,dd) = Trim_CRC(1,Trim_CRC_Counter);
              Trim_CRC_Counter = Trim_CRC_Counter + 1; 
          end

    end

The end needs to be a string with the binary values that I can convert to a decimal or hex number. The two for loop above is giving me a matrix out of bounds errors. Can anyone help me fix this?

Thanks !

[Jan]

As usual: Please post the complete error message an the line, which causes the problems. It is always a good idea to let the contributors guess as less as possible.

Answer 1

[Sean de Wolski]

Pre_CRC(isspace(Pre_CRC)) = []

Answer 2

[Jan]

Look what this code does:

for dd = 1:length(Pre_CRC)
  if (isspace(Pre_CRC(:,dd)) == 1)
    Pre_CRC(:,dd) = [];

Pre_CRC(:,dd) is a vector, as far as I can see. Therefore isspace(Pre_CRC(:,dd)) will be a vector also. Comparing its elements with 1 will not change anything, such that this can be omitted. The if command inserts an all implicitly, if it gets a vector as input. Is this the intended behavior?

Now imagine the above works. Then Pre_CRC(:,dd) = []; removed an element from Pre_CRC. This means that Pre-CRC gets shorter, but the for dd loop runs still until the original length!