Help with making a function.
4 views (last 30 days)
Show older comments
I am trying to create a function that takes a single number and determines if it is a square root or not. If it is a perfect square it takes the square root, and if not it divides by three and rounds down. How do i do that?
this is what I have:
function y = x^2;
if y=1;
z = sqrt(y);
end
else
y/3
0 Comments
Answers (2)
Akira Agata
on 12 Mar 2019
Like this? (Please save the following code as squareRootCheck.m)
function y = squareRootCheck(x)
if mod(sqrt(x),1) == 0
y = sqrt(x);
else
y = floor(x/3);
end
end
0 Comments
Stephen23
on 12 Mar 2019
function y = myfun(x)
y = sqrt(x);
if y~=fix(y)
y = floor(x/3);
end
end
0 Comments
See Also
Categories
Find more on Function Creation in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!