need to do a string interpolation

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Truman Cassady
Truman Cassady on 14 Mar 2019
Answered: Star Strider on 14 Mar 2019
I have six matrices with the same name except a number at the end to distinguish them. I need to access the same element of each one. How can I write logic that would access a matrix but change the last character after each iteration.
unction [] = staticstability()
for k = 1:length(LongLTI)
if LongLTI + k+(1,1)<=0
fprintf('From Table 4.1, the aircraft does have static stability for x_body force with respect to forward speed. \n')
else
fprintf('From Table 4.1, the aircraft does not have static stability for x_body force with respect to forward speed. \n')

Answers (1)

Star Strider
Star Strider on 14 Mar 2019
How can I write logic that would access a matrix but change the last character after each iteration.
No need.
I would concatenate them, and address the same element of each ‘page’ of the concatenated array.
If they are not all the same size, concatenate them as cells:
matrix1 = randi(9, 3, 4);
matrix2 = randi(9, 3, 5);
matrix3 = randi(9, 4, 4);
matrixc = cat(3, {matrix1},{matrix2},{matrix3});
same_element1 = cellfun(@(x)x(2,3), matrixc, 'Uni',0);
same_elementd = squeeze([same_element1])
If they are all the same size, this is even easier:
matrix4 = randi(9, 5, 5);
matrix5 = randi(9, 5, 5);
matrix6 = randi(9, 5, 5);
matrixd = cat(3, matrix4, matrix5, matrix6);
same_element2 = squeeze(matrixd(2,3,:))
Make appropriate changes for your matrices.
This eliminates the problem of creating code that addresses them as dynamic arrays.

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