Missing data values with interpolation
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Hello everybody,
I have a cell array each containing a sequence of diferent values. The sequences contains some missing values (I've represented with NaN). I would like to replace all this NaN places with numbers. I think the better way is do an interpolation but I don't know how to code this Nan and how to save it on a table in Matlab.
I1= interp1(x,y,'linear');
Greetings,
Pd) I've tried this but it doesn't work
nanData = isnan(y);
index = 1:numel(y);
data2 = y;
data2(nanData) = interp1(index(~nanData), y(~nanData), index(nanData));
Accepted Answer
More Answers (2)
Steven Lord
on 15 Dec 2018
2 votes
1 Comment
mostafa mahdi yousef
on 19 Dec 2021
this is the best answer thanks Steven!
like ypu from IRAN!
Andrei Bobrov
on 7 Aug 2012
Edited: Andrei Bobrov
on 8 Aug 2012
eg
data
Data = cell(1,5);
for jj = 1:5
k = [randi(250,randi([10,15]),1); nan(randi([0 3]),1) ];
Data{jj} = k(randperm(numel(k)));
end
solution
for jj = 1:numel(Data)
n = (1:numel(Data{jj}))';
k = ~isnan(Data{jj});
Data{jj} = interp1(n(k),Data{jj}(k),n,'linear','extrap');
end
ADD
load doc1.txt
x = doc1(:,1);
y= doc1(:,2);
t = all(~isnan([x,y]),2);
out = interp1(x(t),y(t),x,'linear','extrap');
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