Adding new field to structure array

I have a structure vector s with already existing fields f1 and f2. I want to perform calculations on those fields for every single element and save results to a new field f3. Can following expressions be simplified?

fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2])
a = num2cell(a)
[s.f3] = a{:}

Answer 1

[Maciej Grybko]

Okay, I figured it out:

fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2], 'UniformOutput',false)
[s.f3] = a{:}

But still, is there any way to combine 2nd and 3rd line?

[madhan ravi]

Isn’t that what Alex posted 30 minutes earlier to this?

Answer 2

[Walter Roberson]

Not really. You could reduce by one line by using

a = num2cell(arrayfun(fun, [s.f1], [s.f2]));

for whatever that is worth.

You could go through struct2cell() and create a new cell with the result, but it is not going to be any simpler than what you already have.

You could do it in fewer lines using especially obscure syntax. I am the only person whom I have seen use that syntax in about a decade -- I posted an example a few months ago just to prove that it could be done -- and that it was not worth doing. It would not be any simpler: it would leave even fairly advanced MATLAB users scratching their heads and wondering, "Can you do that???"

[Alex Mcaulley]

Another option (I don't know which is more efficient):

fun = @(x, y) (x+y)/2
a = arrayfun(fun, [s.f1], [s.f2],'UniformOutput',false);
[s.f3] = a{:}

[Walter Roberson]

That's a good approach.

[madhan ravi]

Sir Walter is that possible using substruct() and subsasgn() ? It would be nice if it’s possible.

[Walter Roberson]

Yes, using subsasgn() is the very obscure syntax I was referring to.

[madhan ravi]

;) knew it , thank you sir Walter.

[Maciej Grybko]

Thanks