NaN with backslash operator
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Hi,
I would like to understand the reason as to why the below operation is giving a NaN solution for the attached data.
x = A\B;
Thank you.
YK..
0 Comments
Accepted Answer
Adam Danz
on 29 Apr 2019
The following rows of your variable "B" contain NaN values.
find(isnan(B))
ans =
1491
1492
1493
1494
1495
1496
1497
To ignore the NaN values,
nanIdx = isnan(A) | isnan(B);
A(~nanIdx) \ B(~nanIdx)
ans =
-0.091457
2 Comments
John D'Errico
on 29 Apr 2019
The problem being that NaNs propagate. Everything they touch, turns to NaN. (Like old King MIdas, but in an even worse way.) So if you already have NaNs in your data, give it up. You need to excise them from your data before any linear algebra computations.
Steven Lord
on 29 Apr 2019
FYI the functions listed in the "Missing Data and Outliers" section of this documentation page may be of use in locating, removing, and/or replacing the NaN values in the data.
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