How to solve a third order polynomial

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Sarah Hicks
Sarah Hicks on 30 Apr 2019
Commented: Star Strider on 30 Apr 2019
I have the correct code to solving this question, but I was wondering why in line 2 there were the numbers 1,2,4,5? I do not understand why those specific numbers are there.
% Output a third-order polynomial function with the coefficients as the
% input variables
x = 0:10;
output = polynomial(x,1,2,4,5); % HELP HERE
% Convert the function to a function handle
poly_handle = @polynomial;
output2 = poly_handle(x,1,2,4,5);
  1 Comment
Star Strider
Star Strider on 30 Apr 2019
I cannot find a built-in function called ‘polynomial’ in the online documentation.
Are you asking about writing the function, or help on using it?

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