Consider the following example. a and b are two random variables. The loop will exit if and only if a+b=1. Is it true or false?
a=rand;
b=rand;
while(a+b == 1)
a=rand;
b=rand;
end

1 Comment

I found that sometimes the sum was exceeding 1 or less than 1. Why?

Sign in to comment.

 Accepted Answer

Walter Roberson
Walter Roberson on 27 Aug 2012

0 votes

While executes as long as the given condition is true, so the loop would only execute as long as the sum was 1.

5 Comments

Sabarinathan Vadivelu
Sabarinathan Vadivelu on 27 Aug 2012
Edited: Sabarinathan Vadivelu on 27 Aug 2012
But sir, I found that when adding both values I'm getting a value greater than 1.
a=0.7849 and b=0.9728. this value I got one time.
If the sum was greater than 1, then a+b == 1 would be false, so your loop as written would not execute, so the values would be left unchanged.
How can I overcome this problem? How to satisfy that condition? It should be a +b = 1. No other values should come.
Jan
Jan on 27 Aug 2012
Edited: Jan on 27 Aug 2012
If a+b must be 1, simply use:
a = rand; b = 1 - a;
It is extremely unlikely that two random numbers will have a sum of 1. I think the probability is in the magnitude of 10^-53. Therefore rejecting the values until the sum equals 1 will take a looong time.
a=rand;
b=rand;
while(a+b ~= 1)
a=rand;
b=rand;
end

Sign in to comment.

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Products

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!