Comparing an array of cells in a matrix

Hello! I need to compare values ​​with each other in cell arrays

for redit = 1:length(xintegra)-1
     if EE1{redit}-100>= EE1{redit+1};
      E1{redit}=0;
      else EE1{redit}+100 <= EE1{redit+1};
      E1{redit}=EE1{redit};  
      end
end

You give an error "Index exceeds matrix dimensions."

Help me fix

[Rik]

Comment posted as answer by Praveen:

What is the input Xintegra?

[Rik]

Reply by Lev Mihailov:

the minimum value of my matrix = 11003, EE1 this is an indicator of where it is located.

Answer 1

[Roy Kadesh]

If you want loop through all values of EE1, then you can use the code below.

for redit = 1:numel(EE1)-1
    if EE1{redit}-100>= EE1{redit+1}
        E1{redit}=0;
    elseif EE1{redit}+100 <= EE1{redit+1} %did you mean elseif?
        E1{redit}=EE1{redit};
    end
end

If you want to catch the case where redit is larger than the numer of elements in EE1, you can fill in the code below.

for redit = 1:numel(xintegra)-1
    if (redit+1)>numel(EE1)
        %do something else
    else
        if EE1{redit}-100>= EE1{redit+1}
            E1{redit}=0;
        elseif EE1{redit}+100 <= EE1{redit+1} %did you mean elseif
            E1{redit}=EE1{redit};
        end
    end
end

[Rik]

If there are indeed only numeric values inside that cell array, it is probably much faster to convert it to a double and use logical indexing to create the output.