Checking the variable for specific string
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Ravikumar Mevada
on 31 Jul 2019
Very new to Matlab. I need to give 'high' or 'low' in one function's input as shown below. How can I make sure that the variable only accept 'high' or 'low'? If anything else, then there will be an error like 'filter type error'.
Using code bellow, gives error even with 'high' and 'low' input.
Thanks!
function [Y] = butter2filtfilt(x, Fs, Fcutoff, Type)
if Type~= "high" || Type~= "low"
error ('Filter type error')
end
end
>> LF = butter2filtfilt(ecg, 257, 0.15, 'low');
Error using butter2filtfilt (line 6)
Filter type error
1 Comment
Steven Lord
on 31 Jul 2019
You've received a couple alternative solutions, but as an explanation for why this doesn't work that if statement is equivalent to "If type is not equal to 'high' or type is not equal to 'low', throw an error".
So what if type is equal to 'high'? The "type is not equal to 'high'" portion of that sentence is false, but the "type is not equal to 'low'" portion is true. Since the condition is false or true, the if is satisfied and so you throw an error.
The same holds if type is equal to 'low', just in reverse order. The first portion is true and the second portion is false.
You want to error if type is not equal to 'high' and type is not equal to 'low', not if one or the other is true.
Accepted Answer
Alex Mcaulley
on 31 Jul 2019
function [Y] = butter2filtfilt(x, Fs, Fcutoff, Type)
if ~ismember(Type,{'high','low'})
error ('Filter type error')
end
end
5 Comments
madhan ravi
on 31 Jul 2019
"How can I make sure that the variable only accept 'high' or 'low'? If anything else, then there will be an error like 'filter type error'. "
More Answers (1)
Adam Danz
on 31 Jul 2019
Edited: Adam Danz
on 31 Jul 2019
This solution uses strcmpi() which which compares strings, allowing for case insensitivity so "High" or "LOW" won't cause an error. When there is an error, it provides the "Type" string that caused the error.
function [Y] = butter2filtfilt(x, Fs, Fcutoff, Type)
options = ["high", "low"];
if ~any(strcmpi(Type, options))
error('Filter type error. ''%s'' not recognized.', Type)
end
end
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